Question 44
The perimeters of two similar triangles ABC and PQRare 78 cm and 46.8 cm, respectively. If PQ = 11.7, then the length of AB is:
Solution
Triangles ABC and PQR are similar.
So,
$$\frac{perimeter of ABC}{perimeter of PQR} = \frac{side of ABC}{side of PQR}$$
$$\frac{78}{46.8} = \frac{AB}{11.7}$$
$$\frac{78}{46.8} \times 11.7 = AB$$
AB = 19.5 cm
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