Question 44

A bag contains 4 red, 5 yellow and 6 pink balls. Two balls are drawn at random. What is the probability that none of the balls drawn are yellow in colour?

Solution

Number of non-yellow balls = 4 + 6 = 10
Required Probability = $$\frac{^{10}C_2}{^{15}C_2} = \frac{3}{7}$$


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