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Which of the following circuits has the same output as that of the given circuit?
For the given circuit, $$Y = \overline{A\bar{B} + AB}$$
$$Y = \overline{A(\bar{B} + B)} \implies Y = \overline{A(1)} = \bar{A}$$
Option (B) represents a NAND gate with shorted inputs acting as a NOT gate: $$Y = \overline{A \cdot A} = \bar{A}$$
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