Question 42

The HCF of 24, 60 and 90 is:

Solution

You need to calculate the prime factor of each number individually,

Hence,

24 = $$2\times 2\times 2\times 3\times 1$$

60 = $$2\times 2\times 3\times 5\times 1$$

90 = $$2\times 3\times 3\times 5\times 1$$

Common number among the set = $$2\times 3\times 1 = 6$$

Hence, the HCF = 6

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