In university L,$$ \frac{5}{12} $$of the Assistant Professors are males and in university M, $$\frac{5}{11} $$of the Assistant professors are males. What is the respective ratio between male Assistant Professors in university L and that in university M?
Solution
Number of Assistant Professors in university L = $$\frac{60}{100} \times 160 = 96$$
=> Male assistant professors = $$\frac{5}{12} \times 96 = 40$$
Number of Assistant Professors in university M = $$\frac{55}{100} \times 180 = 99$$
=> Male assistant professors = $$\frac{5}{11} \times 99 = 45$$
$$\therefore$$ Required ratio = $$\frac{40}{45} = 8 : 9$$
