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If $$3^x = 4^{x - 1}$$, then x =
$$\frac{2 \log_3 2}{2 \log_3 2 -1}$$
$$\frac{2}{2 - \log_2 3}$$
$$\frac{1}{1 - \log_4 3}$$
$$\frac{2 \log_2 3}{2 \log_2 3 - 1}$$
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