There are three boxes of three different colors - Green, Blue and Red, and 6 toys of which 2 are of Green colour, 2 are of Blue colour and 2 are of Red colour. The toys are packed in the three boxes such that each box has 2 toys of different colours in it and also the colour of the box is different from the colour of the toys packed in it. Now, 10 chocolates are kept in these boxes in such a way that the Green box has the maximum possible chocolates in it whereas, the Red box has the least possible chocolates in it. Each box should have at least one chocolate and no two boxes have the same number of chocolates.

Determine which of the following is definitely true ?

Boxes have 2 toys which are of different colors to each other and to the color of box.

so Green box has 1 red toy and 1 blue toy

Blue box has 1 red toy and 1 green toy

Red box has 1 blue toy and 1 green toy

Also

so Green Box should have maximum possible chocolates and the Red box has the least possible chocolates in it. Such that each box has at least one chocolate and no two boxes have equal number of chocolates.

so to minimize chocolates minimum 1 chocolate needs to be there in it. In blue box, in order to maximize chocolates in green box, needs to have only 2 chocolates ( as no two boxes have equal number of chocolates and minimum we can put now here is 2 chocolates ) and finally the green box will have 7 chocolates left which is the maximum that can be done.

Therefore option c : 'The box ( blue colored box )  which has the toys of Green and Red colors has 2 chocolates in it' is correct