Question 41

The difference between the ages of two sisters is 2 years when father's age was 52. Father is elder by 2 years to mother. Elder sister's age is half of mother's age. Find the age of younger sister.

Solution

Let the elder sister's age be x and younger sister's age be y

Given that difference between two the ages of to sisters is 2 years

⇒ x - y = 2

Given that father's age is 52, then mother's age = 50

Also given that elder sister's age x = half of the mother's age = $$\frac{50}{2}$$ = 25

Substitute x = 25 in x - y = 2

⇒ 25 - y = 2

⇒ y = 25 - 2 = 23

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