Question 41

12 men finished 1/4 part of whole work in 6 days. Find the number of additional men required to complete the job in next 6 days.

Solution

$$M_1=12, D_=6, W_1=\frac{1}{4}$$

$$M_2=?, D_2=6, W_2=1-\frac{1}{4}=\frac{3}{4}$$

We have

$$\frac{M_1D_1}{W_1}=\frac{M_2D_2}{W_2}$$

$$\frac12\times6=\frac{M_2\times6}{\frac{3}{4}}$$

$$M_2=36$$

Hence No. of additional men required=36-12=24

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