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The value of $$\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \frac{x^2 \cos x}{1 + e^x}dx$$ is equal to
$$\frac{\pi^2}{4} - 2$$
$$\frac{\pi^2}{4} + 2$$
$$\pi^2 - e^{\frac{\pi}{2}}$$
$$\pi^2 + e^{\frac{\pi}{2}}$$
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