Question 39

The value of $$\sum_{k = 1}^{13} \frac{1}{\sin\left(\frac{\pi}{4} + \frac{(k - 1)\pi}{6}\right)\sin\left(\frac{\pi}{4} + \frac{k \pi}{6}\right)}$$ is equal to


Create a FREE account and get:

  • Free JEE Advanced Previous Papers PDF
  • Take JEE Advanced paper tests

cracku

Boost your Prep!

Download App