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Area of the region $$\left\{(x, y) \epsilon R^2 : y \geq \sqrt{\mid x + 3 \mid}, 5y \leq x + 9 \leq 15\right\}$$ is equal to
$$\frac{1}{6}$$
$$\frac{4}{3}$$
$$\frac{3}{2}$$
$$\frac{5}{3}$$
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