If $$6\alpha1 = 70, 2\alpha3 = 50$$ and $$4\alpha5 = 90$$, then find the value of $$4\alpha1 = ?$$
Given : $$6\alpha1 = 70, 2\alpha3 = 50$$ and $$4\alpha5 = 90$$
If we replace $$'\alpha'$$ with '+', and multiply the sum by 10, we get the desired result.
Eg :- $$(6+1)\times10=70$$
and $$(2+3)\times10=50$$ and $$(4+5)\times10=90$$
Similarly, $$(4+1)\times10=50$$
=> Ans - (A)
Create a FREE account and get:
