Question 40

If $$6\alpha1 = 70, 2\alpha3 = 50$$ and $$4\alpha5 = 90$$, then ﬁnd the value of $$4\alpha1 = ?$$

Solution

Given : $$6\alpha1 = 70, 2\alpha3 = 50$$ and $$4\alpha5 = 90$$

If we replace $$'\alpha'$$ with '+', and multiply the sum by 10, we get the desired result.

Eg :- $$(6+1)\times10=70$$

and $$(2+3)\times10=50$$ and $$(4+5)\times10=90$$

Similarly, $$(4+1)\times10=50$$

=> Ans - (A)

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