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Question 4
What is the value of $$\frac{(1.2)^3 + (0.8)^3 + (0.7)^3 - 2.016}{1.35[(1.2)^2 + (0.8)^2 + (0.7)^2 - 0.96 - 0.84 - 0.56]}$$ ?
Solution
$$x^3 + y^3 + z^3 -3xyz$$=$$(x + y + z )(x^{2}+y^{2}+z^{2}-xy-yz-zx)$$
x=1.2 y=0.8 z=0.7
$$\frac{(1.2)^3 + (0.8)^3 + (0.7)^3 - 2.016}{1.35[(1.2)^2 + (0.8)^2 + (0.7)^2 - 0.96 - 0.84 - 0.56]}$$
=$$\frac{((2.7)((1.2)^2 + (0.8)^2 + (0.7)^2 - 0.96 - 0.84 - 0.56)}{1.35[(1.2)^2 + (0.8)^2 + (0.7)^2 - 0.96 - 0.84 - 0.56]}$$
=2.7/1.35
=2
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