The value of $$\frac{(0.545)(0.081)(0.51)(5.2)}{\left(0.324\right)^3+\left(0.221\right)^3-\left(0.545\right)^3}$$ is:
$$\frac{(0.545)(0.081)(0.51)(5.2)}{\left(0.324\right)^3+\left(0.221\right)^3-\left(0.545\right)^3}$$
=Â $$\frac{(0.545)(0.081)(0.51)(5.2)}{3(0.324)(0.221)(0.545)}$$
$$(\because (a + b)^3 = a^3 +Â b^3 + 3ab(a + b))$$
=Â $$\frac{(0.081)(0.51)(5.2)}{3(0.324)(0.221)}$$ = 1
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