In $$ \triangle $$ ABC, AB = 10cm, $$ \angle $$ A is bisected internally BC at D. BD = 6 cm and DC = 7.5 cm. What is the length of CA?
In a triangle internal bisector divides the opposite side in the ratio of other two sides i.e
AB/BC=BD/DC
10/AC=6/7.5
AC=10*7.5/6
AC=75/6
AC=12.5 cm
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