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The Fourier transform of a signal $$x(t) = e^{-4\mid t \mid}$$
$$\frac{8}{16 + \omega^{2}}$$
$$\frac{-8}{16 - \omega^{2}}$$
$$\frac{4}{16 + \omega^{2}}$$
$$\frac{-4}{16 + \omega^{2}}$$
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