Question 38

If $$8^{th}$$ February, 2005 was a Tuesday, then what was the day on $$8^{th}$$ February, 2004?

Solution

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Let us assume the day on $$8^{th}$$ February, 2004 is X

And, since 2004 is a leap year so, it will have one extra day = 365+1 = 366 days till 8th February, 2005

So, number of odd days = 366/7 = 2 days

So on $$8^{th}$$ February, 2005, it will be X+2 day and it is Tuesday.

Therefore, X = Sunday

Hence, on $$8^{th}$$ February, 2004 it was sunday.

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