For the conversion $$\mathrm{CCl_4(l)\rightarrow CCl_4(g)}$$ at $$1\ \mathrm{bar}$$ and $$350\ \mathrm K$$, the correct set of thermodynamic parameters is, given boiling point of $$\mathrm{CCl_4}$$ is $$77^\circ\mathrm C$$

A

$$\Delta G=0,\ \Delta S =  ^{+}ve$$

B

$$\Delta G=0,\ \Delta S = ^{-}ve$$

C

$$\Delta G=^{-}ve,\ \Delta S=0$$

D

$$\Delta G=^{-}ve \Delta S = ^{+}ve$$