Question 37
A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is,
Solution
Total distance = 108+112 = 220m
Total time = 6 seconds
Now we know that :
Relative speed = Distance / Time
so we get :
220/6 = v1+v2
110/3 =125/9 + v
we get v = $$\ \frac{\ 205}{9}$$m/s =$$=\ \frac{\ 205}{9}\times\ \ \frac{\ 18}{5}=$$ 82km/hr
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