Question 36

Find the largest number of three digits exactly divisible by 15, 18, 27 and 30.

Solution

we have to find lcm of the numbers

15 = $$3\times 5$$

18 = $$2\times 3\times 3$$

27 = $$3\times 3\times 3$$

30= $$2\times 3\times 5$$

so, lcm = $$2\times 3\times 3\times 3\times 5$$

= 270

so, 810 is the only number divisible by 270

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