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Find the largest number of three digits exactly divisible by 15, 18, 27 and 30.
we have to find lcm of the numbers
15 = $$3\times 5$$
18 = $$2\times 3\times 3$$
27 = $$3\times 3\times 3$$
30= $$2\times 3\times 5$$
so, lcm = $$2\times 3\times 3\times 3\times 5$$
= 270
so, 810 is the only number divisible by 270
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