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A constant horizontal force acts on a body of mass $$9\text{ kg}$$ lying at rest on a smooth horizontal surface for $$10\text{ s}$$. If the body moves $$25\text{ m}$$ in this time, the magnitude of the force is
From $$s = \frac{1}{2}at^2$$, $$25 = \frac{1}{2} \times a \times 10^2$$, so $$a = 0.5\text{ ms}^{-2}$$. The force is $$F = ma = 9 \times 0.5 = 4.5\text{ N}$$.
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