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The mass of a spherical planet is 8 times that of the earth and its density is same as that of earth. The acceleration due to gravity (in $$\text{ms}^{-2}$$) on the surface of this planet will be (gravity on earth is $$9.8\text{ ms}^{-2}$$)
With the same density, 8 times the mass means 8 times the volume, so the radius is doubled. Since $$g = \frac{GM}{R^2}$$, the new value is $$\frac{8}{2^2} \times 9.8 = 2 \times 9.8 = 19.6\text{ ms}^{-2}$$.
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