Solution
Pythagorean triplet
$$A^2+B^2=C^2$$
$$8^2+15^2=17^2$$
$$64+225=289$$
$$289=289$$
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Pythagorean triplet
$$A^2+B^2=C^2$$
$$8^2+15^2=17^2$$
$$64+225=289$$
$$289=289$$
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