If 11 @ 7 = 2, 18 @ 0 = 9 and 22 @ 20 = 1, then find the value of 16 @ 10 = ?
Given, 11 @ 7 = 2, 18 @ 0 = 9 and 22 @ 20 = 1
The logic here is
$$\frac{11-7}{2}=2$$
$$\frac{18-0}{2}=9$$
$$\frac{22-20}{2}=1$$
The code value is the half the difference of the given numbers.
Similarly,
$$\frac{16-10}{2}=3$$
$$\therefore\ $$16 @ 10 = 3
Hence, the correct answer is Option D
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