Question 34

Find the value of $$ \frac{sin 30^\circ 17'}{cos 59^\circ 43'} - \frac{cosec 32}{sec 58^\circ} $$

Solution

$$ \frac{sin 30^\circ 17'}{cos 59^\circ 43'} - \frac{cosec 32}{sec 58^\circ} $$

$$ \frac{sin 30^\circ 17'}{cos (90 - 30^\circ 17')} - \frac{cosec 32}{sec (90 - 32)^\circ} $$

$$ \frac{sin 30^\circ 17'}{sin 30^\circ 17'} - \frac{cosec 32}{cosec 32} $$ = 1 -1 = 0

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