Mohan is thrice as efficient as Srinu and completes a work in 40 hours less than the time taken by Srinu. If both of them work together, the time (in hours) required to complete that work is
Let,Srinu takes x hour to complete work.
then Mohan takes x/3 hour to complete the work.
According to question,
$$x\ -40=\frac{x\ }{3}.$$
or,$$x\ -\frac{x\ }{3}=40.$$
or,$$\frac{2x\ }{3}=40.$$
or,$$x\ =60.$$
Then,they will do in 1 hour $$\ \frac{\ 1}{20}+\frac{1\ }{60}=\frac{3+1\ }{60}=\frac{4\ }{60}=\frac{1`\ }{15}$$ part.
So, they together will complete in 15 hour.
C is correct choice.
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