Sign in
Please select an account to continue using cracku.in
↓ →
Mohan is thrice as efficient as Srinu and completes a work in 40 hours less than the time taken by Srinu. If both of them work together, the time (in hours) required to complete that work is
Let,Srinu takes x hour to complete work.
then Mohan takes x/3 hour to complete the work.
According to question,
$$x\ -40=\frac{x\ }{3}.$$
or,$$x\ -\frac{x\ }{3}=40.$$
or,$$\frac{2x\ }{3}=40.$$
or,$$x\ =60.$$
Then,they will do in 1 hour $$\ \frac{\ 1}{20}+\frac{1\ }{60}=\frac{3+1\ }{60}=\frac{4\ }{60}=\frac{1`\ }{15}$$ part.
So, they together will complete in 15 hour.
C is correct choice.
Was this solution helpful?
Create a FREE account and get:
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation