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If a right triangle is right angled at A and AC = 6, BC = 10, find the value of $$\tan B \times \tan C$$.
$$ \tan B = \frac{6}{8} $$
$$ \tan c = \frac{8}{6} $$
$$ \tan B \times \tan C = \frac{6}{8} \times \frac{8}{6} $$
= 1
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