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Question 31
What is the greatest number which divides 1070 and 1265 and leaves remainders 3 and 4 respectively?
Solution
The required number is the HCF of (1070 - 3, 1265 - 4) = HCF of (1067, 1261)
1067 = 11*97 and 1261 = 13*97
So, HCF = 97
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