Question 31

The LCM and HCF of 2 numbers are 168 and 6 respectively. If one of the numbers is 24, find the other.

Solution

$$multiplication\ of\ two\ numbers=LCM\times HCF\ of\ these\ two\ numbers.$$

here, LCM=168 and HCF=6 and one of the number is 24.

So,$$other\ number\times24=168\times6.$$

or,$$other\ number=\frac{\left(168\times6\right)}{24}=42.$$

So,D is correct choice.

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