Question 31
The LCM and HCF of 2 numbers are 168 and 6 respectively. If one of the numbers is 24, find the other.
Solution
$$multiplication\ of\ two\ numbers=LCM\times HCF\ of\ these\ two\ numbers.$$
here, LCM=168 and HCF=6 and one of the number is 24.
So,$$other\ number\times24=168\times6.$$
or,$$other\ number=\frac{\left(168\times6\right)}{24}=42.$$
So,D is correct choice.
Get AI Help
Create a FREE account and get:
- Download RRB Study Material PDF
- 45+ RRB previous papers with solutions PDF
- 300+ Online RRB Tests for Free
