A = $$\frac{2}{10}\times\frac{2}{10}\times\frac{2}{10} =Â \frac{8}{1000}$$
B = $$\frac{0.02}{3} = \frac{2}{100\times3} =Â \frac{20}{3000} =Â \frac{6.666}{1000}$$C = $$\frac{0.01}{2} = \frac{1}{200} = \frac{0.5}{100}=Â \frac{5}{1000}$$
D = $$\frac{1}{10}\times \frac{2}{100}\times 2 = \frac{4}{1000}$$
Since all the denominators are the same, the number with the lowest numerator will be the smallest fraction.
Hence option D.
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