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Electrons of mass m with de-Broglie wave length $$\lambda$$ fall on the target in an X-ray tube. The cutoff wavelength $$(\lambda_0)$$ of the emitted X-ray is
$$\lambda_0=\frac{2h}{mc}$$
$$\lambda_0=\frac{2m^{2}c^2\lambda^2}{h^2}$$
$$\lambda_0=\lambda$$
$$\lambda_0=\frac{2mc\lambda^2}{h}$$
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