Question 31

68, ?, 77, 104, 168, 293

Solution

Cubes of consecutive natural numbers are added

68 $$+ 1^3$$ = 69

69 $$+ 2^3$$ = 77

77 $$+ 3^3$$ = 104

104 $$+ 4^3$$ = 168

168 $$+ 5^3$$ = 293


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