Question 30

The remainder, when $$(15^{23} + 23^{23})$$ is divided by 19, is

Solution

The remainder when $$15^{23}$$ is divided by 19 equals $$(-4)^{23}$$
The remainder when $$23^{23}$$ is divided by 19 equals $$4^{23}$$
So, the sum of the two equals$$(-4)^{23}+(4)^{23}=0$$

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The remainder, when $$(15^{23} + 23^{23})$$ is divided by 19, is

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