How many solutions does a pair of linear equations will have, if the equations are
7x+4y-16=0 and 14x+6y-32=0?
Equations :Â 7x+4y-16=0 and 14x+6y-32=0
Comparing the ratio of coefficients of both equations,
=> $$\frac{7}{14}\neq\frac{4}{6}$$
Thus, there is only 1 solution.
=> Ans - (B)
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