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Find the factors of $$(x^2 + x - 42)$$
$$(x + 14)(x - 3)$$
$$(x + 6)(x - 7)$$
$$(x - 6)(x + 7)$$
$$(x - 14)(x + 3)$$
$$(x^2 + x - 42)$$
$$x^2+7x-6x-42=0$$
$$x(x+7)-6(x+7)=0$$
$$(x-6)(x+7) =0$$
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