Solution
$$(x^2 + x - 42)$$
$$x^2+7x-6x-42=0$$
$$x(x+7)-6(x+7)=0$$
$$(x-6)(x+7) =0$$
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$$(x^2 + x - 42)$$
$$x^2+7x-6x-42=0$$
$$x(x+7)-6(x+7)=0$$
$$(x-6)(x+7) =0$$
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