SSC MTS 17 March 2013 Shift 2 Question 3

Question 3

ADIP : DGLS :: BEJQ : ?

Solution

The pattern followed here is (n + 3),

A + 3 = D, D + 3 = G, I + 3 = L, P + 3 = S

BEJQ can be written as,

B + 3 = E, E + 3 = H, J + 3 = M, Q + 3 = T

Hence, option A is the correct answer.



Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

Comments

Register with

OR

Boost your Prep!

Download App