A thin uniform circular ring of mass $$m$$ is rolling without slipping down an inclined plane of inclination $$30^\circ$$ with the horizontal. The coefficient of friction between the ring and the surface is $$\mu$$. The correct statement is

A

linear acceleration of the center of the ring along the plane is $$a = \frac{g}{2}$$

B

force of friction between the ring and the inclined plane is $$F_{\text{friction}} = \frac{mg}{4}$$

C

the ring keeps rolling for all values of the coefficient of friction $$\mu \ge \frac{1}{4}$$

D

linear acceleration of the center of the ring along the plane is $$a = \frac{g}{3}$$