A solid cylinder of radius $$R$$ rolls without slipping with a center of mass speed $$v_0=\sqrt{\dfrac{gR}{3}}$$ on a horizontal surface with a vertical edge, as shown in the figure. Here, $$g$$ is the acceleration due to the gravity. At the moment when the cylinder loses contact with the surface due to rotation around the corner, the speed of its center of mass is:

A

$$0$$

B

$$\sqrt{\dfrac{5gR}{7}}$$

C

$$\sqrt{\dfrac{gR}{15}}$$

D

$$\sqrt{\dfrac{3gR}{7}}$$