Two children differ in their age by 2 years. Six years later, the sum of their ages will be 46. How old are they now?
Let the ages of children be 'x' and 'x-2'
6 years later , ages of children be 'x+6' and 'x+4'
x+6+x+4 = 46
$$ 2x+10 = 46 $$
x=$$ \frac{36}{2} $$
x= 18
x-2=16
At present age of children = 18-6,16-6
                    = 12 , 10
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