In the circuit shown, the Zener diode is an ideal one with breakdown voltage of $$5.0\,\text{V}$$. The values of the resistances are $$R_S = 10\,\text{k}\Omega$$ and $$R_L = 1\,\text{k}\Omega$$. The current through the resistances, when the supply voltage is $$11.0\,\text{V}$$, is

A

$$0.6\,\text{mA}$$ through $$R_S$$ and $$5.0\,\text{mA}$$ through $$R_L$$

B

$$1.0\,\text{mA}$$ through $$R_S$$ and $$1.0\,\text{mA}$$ through $$R_L$$

C

$$1.1\,\text{mA}$$ through $$R_S$$ and no current through $$R_L$$

D

no current through $$R_S$$ and $$11\,\text{mA}$$ through $$R_L$$