Question 28

If 19 + 4 # 5 = 39 and 21 # 5 + 6 = 111, then 11 + 15 # 5 = ?

Solution

Given : 19 + 4 # 5 = 39 and 21 # 5 + 6 = 111

If we replace '#' with 'x', then we get the desired result.

Eg :- $$19+(4\times5)=39$$

and $$(21\times5)+6=111$$

Similarly, $$11+(15\times5)=86$$

=> Ans - (D)

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