Question 28

If 14 # 3 @ 4 =46 and 19 # 4 @ 3 =79, then 21 # 4 @ 1 =?

Solution

The pattern followed is : a#b@c = $$(a\times b)+c$$

Eg :- 14 # 3 @ 4 = $$(14\times3)+4=42+4=46$$

and 19 # 4 @ 3 = $$(19\times4)+3=76+3=79$$

Similarly, 21 # 4 @ 1 = $$(21\times4)+1=84+1=85$$

=> Ans - (C)

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