Which of the following interchanges of signs and numbers would make the given equation correct?
$$12\div 4+2-6\times3=3\div12+6\times2-4$$

A

$$-\ and\ +,6\ and\ 4$$

B

$$\div\ and\ +,6\ and\ 4$$

C

$$\times\ and \ -,4\ and \ 6$$

D

$$\times\ and \ \div,4\ and \ 6$$