If $$\tan (A + B) = 0$$, then-

A

$$\frac{2 \tan A + \tan B}{1 - \tan A \tan B} = 1$$

B

$$\tan A + \tan B = 0$$

C

$$\frac{2 \tan A + \tan B}{1 + \tan A \tan B} = 0$$

D

$$\tan A = \tan B$$