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If $$\tan (A + B) = 0$$, then-
$$\frac{2 \tan A + \tan B}{1 - \tan A \tan B} = 1$$
$$\tan A + \tan B = 0$$
$$\frac{2 \tan A + \tan B}{1 + \tan A \tan B} = 0$$
$$\tan A = \tan B$$
this is a formula of trignometry
$$\tan (A + B) = 0$$
$$\frac{tanA + tanB}{1 - tanA\times tanB}$$ = 0
tanA + tanB = 0
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