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A contract is to be completed in 50 days and 105 men were set to work, each working 8 hours a day. After 25 days, $$\frac{2}{5}th$$ of the work is finished. How many additional men be employed so that the work may be completed on time, each man now working 9 hours a day?
It is given that in the initial 25 days, the work done by 105 men was $$(2/5)^{th}$$ of the total work.
Thus, the total work left is $$(3/5)^{th}$$ of the total work.
MDH/W is constant
so we get
$$\frac{105\times\ 25\times\ 8}{\frac{2W}{5}}=\frac{M\times\ 25\times\ 9}{\frac{3W}{5}}$$
We get M =140
So additional men = 140-105 = 35
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