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The product $$8\mathbin{\times}9\mathbin{\times}10\mathbin{\times}11\mathbin{\times}12\mathbin{\times}13\mathbin{\times}14$$ can also be written as a product of another sequence of consecutive positive integers. The smallest number in that product is
Correct Answer: 63
Factorising or multiplying shows $$8\mathbin{\times}9\mathbin{\times}10\mathbin{\times}11\mathbin{\times}12\mathbin{\times}13\mathbin{\times}14=17297280$$. Also, $$63\mathbin{\times}64\mathbin{\times}65\mathbin{\times}66=17297280$$. Thus the alternate consecutive product begins with $$63$$.
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