Question 247

What would be the measure of the diagonal of a square whose area is equal to 882 $$cm^{2}$$ ?

Solution

Let the side of the square be a

$$a^2 = 882$$

a = $$\sqrt{882}$$ =$$21\sqrt{2}$$

Diagonal =$$\sqrt{2}a$$ = $$21\sqrt{2}\sqrt{2}$$ = 42

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