Question 24

∆XYZ is right angled at Y. If m∠Z = 60°, then find the value of (cotX -­ 1/3).

Solution

Sum of angles of $$\triangle$$ XYZ = $$\angle X+\angle Y+\angle Z=180^\circ$$

=> $$60^\circ+90^\circ+\angle X=180^\circ$$

=> $$\angle X=180^\circ-150^\circ=30^\circ$$

To find : $$(\cot X -\frac{1}{3})$$

= $$cot(30^\circ)-\frac{1}{3}$$

= $$\sqrt3-\frac{1}{3}$$

= $$\frac{(3\sqrt3-1)}{3}$$

=> Ans - (A)


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