Question 24

$$\triangle ABC$$ is right angled at $$B$$. If $$m\angle c=60^\circ$$, then find the value of $$(\cot A-\frac{1}{2})$$ ?

Solution

Given : $$\triangle$$ ABC is a right angled at B and $$\angle C=60^\circ$$

=> $$\angle A=30^\circ$$

=> $$cot A=cot(30^\circ)=\sqrt3$$

To find : $$CotA-\frac{1}{2}$$

= $$\sqrt3-\frac{1}{2}$$

= $$\frac{(2\sqrt3-1)}{2}$$

=> Ans - (C)

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: