Question 24
$$\triangle ABC$$ is right angled at $$B$$. If $$m\angle c=60^\circ$$, then find the value of $$(\cot A-\frac{1}{2})$$ ?
Solution
Given : $$\triangle$$ ABC is a right angled at B and $$\angle C=60^\circ$$
=>Â $$\angle A=30^\circ$$
=> $$cot A=cot(30^\circ)=\sqrt3$$
To find : $$CotA-\frac{1}{2}$$
= $$\sqrt3-\frac{1}{2}$$
= $$\frac{(2\sqrt3-1)}{2}$$
=> Ans - (C)
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